Python如何替换list中的字符
发布网友
发布时间：2022-04-23 04:11
共5个回答
热心网友
时间：2022-04-18 04:53
利用re库进行正则表达替换，python3.4中
import rea = ["123" , "456" , "7"]
d = {"B":"2","E":"5","H":"8"}
b = ",".join(a)
print (b)
for i in d.keys():
b = re.sub(d[i],i,b)
print (b.split(","))
热心网友
时间：2022-04-18 06:11
import re
a = ["!-*%" , ".#7&33&" , "#*#71%"]
d = {"A":"#","N":"%","M":"\*"}
b = ",".join(a)
print b
for i in d.keys():
b = re.sub(d[i],i,b)
print b.split(",")
热心网友
时间：2022-04-18 07:45
[str(j) for j in list if j]使用列表解析处理下这样的问题
热心网友
时间：2022-04-18 09:37
假定list为 x
x = [c.replace('#','A') for c in x]
热心网友
时间：2022-04-18 11:45
For s in list: for c in s: if c ==...这样呢？
